In a certain class, percentage of students who increased their average grade during spring term compared to that of the fall term was recorded between 6.9% and 7.1%. What could be the least possible number of students in that class?
No, you have to consider that if 1 student in 14/15 cannot represent a percentage between .69 and .71, how could 2 students do the job? You have to have an integer number of students.
2/18 = 1/14 = 7.14%
2/29 = 6.89%
Still out of bounds
What about 3 students?
3/42 = 1/14 = 7.14%
3/43 = 6.97%
3/44 = 6.81%
So, it looks like 43 is the minimum number of students.
so would you round it?
To determine the least possible number of students in the class, we need to consider the range of percentages given (6.9% to 7.1%) and how it relates to the total number of students.
Let's assume the total number of students in the class is 'x'. To find the minimum number of students, we'll assume that the percentage is at its minimum value of 6.9%.
This would mean that 6.9% of 'x' students increased their average grade. In other words, the number of students who improved their grades would be 0.069x.
We can calculate this by multiplying the percentage (6.9% or 0.069) by the total number of students ('x').
Now, since we're looking for a whole number of students, we need to round up to the nearest whole number. This is because you can't have a fraction of a student.
Therefore, the minimum possible number of students in the class is:
number of students = ceil(0.069x), where ceil refers to rounding up to the nearest whole number.
To find the exact minimum value, we would need more information about the class, such as the number of students who increased their average grade.
well,
1/.069 = 14.4
1/.071 = 14.08
if 1 out of 15 made it, that would 6.67%
if 1 out of 14 made it, that would be 7.14%
So, how do you think you have to adjust things?