without running on java, what is the final answer, please show your work.
public class sample {
public static void main(String[] args){
Sample x = new Sample();
int i = 10;
int b = x.g(i);
System.out.println(b + i);
}
public int f(int d){
int n = 0;
while(n*n < d){
n++;
}
return n-1;
}
public int g(int a){
int b = 0;
int c;
for(int n = 0; n < a; n++){
c = f(n);
b = b + c;
}
return b;
}
}
Recording all values of the variables in each method as we go:
-main:
i = 10
b = x.g(10) = 12 (returned from g)
---
after method g
i = 10
b = 12*
-f:
d = 0(passed from g's c variable)
n = 0
-while loop-
1st pass:
false, as 0*0 is not <0
n = n - 1 = 0 - 1 = -1
.
.
.
Keep comparing until n^2 is less than d passed in
-g:
a = 10 (passed from main's b variable)
b = 0;
c = NULL;
-for loop-
...n = 0
...c = f(0) = -1 (returned from f's return statement, 1st pass)
...b = b + c = 0 + -1 = -1
(And now after the first pass our variables are:
a = 10
b = -1
c = -1)
This continues until n=9 for n !>= 10
...b = 12
return b; // b is 12, and now we return to main
----------------------------------------------------------------------------------------
b + i = 12 + 10 = 22**
We are really only needing to find what b is, since i does not change in main. It's a lot of back and forth between method g and method f for b but we got it!
This seems like a lot but it's mostly pattern recognition bc of all the loops. It really helps to write down variables and update their values as you go thru code, just a tip.
Also, if you can, paste this into java and add print statements like: "b before adding" and "b after adding", etc. to see how, where, and why these variables change.
thanks @.
To find the final answer without running the code in Java, we need to understand what the code does and then manually calculate the result.
The code provided is a Java program that consists of two methods, "f" and "g," and a main method that calls these methods.
The method "f" takes an integer input "d" and returns an integer result. It initializes a variable "n" to 0 and then enters a while loop. In each iteration, it increments "n" by 1 until the square of "n" is greater than or equal to "d." Finally, it returns "n-1."
The method "g" takes an integer input "a" and returns an integer result. It initializes variables "b" and "c" to 0. Then, it enters a for loop that iterates from 0 to "a." In each iteration, it assigns the result of calling method "f" with the current value of "n" to "c" and adds "c" to "b." Finally, it returns "b."
In the main method, an instance of the class "Sample" is created. The variable "i" is initialized to 10. Then, the method "g" is called with "i" as the parameter, and the result is assigned to variable "b." Finally, the sum of "b" and "i" is printed.
To manually calculate the final answer without running the code in Java, we need to follow these steps:
1. Assign 10 to variable "i."
2. Create an instance of the class Sample.
3. Call method "g" with "i" as the parameter.
4. Inside method "g":
- Initialize variable "b" to 0.
- Enter a for loop that iterates from 0 to 10 (inclusive).
- In each iteration:
- Assign the result of calling method "f" with the current value of "n" to variable "c."
- Add "c" to "b."
- Return the value of "b."
5. Calculate the value of variable "b" by following the steps in method "g."
6. Calculate the sum of the value of variable "b" and the value of variable "i."
7. Print the result of the sum calculated in step 6.
By following these steps, you should be able to manually calculate the final answer without running the code in Java.