Phosphorus pentachloride is produced by the reaction b/w phosphine and chlorine gas.what mass of chlorine gas would be required to produced 0.015kg of phosphorus pentachloride

I solved the problem and I got 20.44g of chlorine gas

2PH3 + 8Cl2 ------> 2PCl5 + 6HCl

0.015kg of PCl5=15g of PCl5

15g of PCl5*(1 mole/208.24 g)=0.07203 moles of PCl5

The reaction shows that 2 moles of PCl5=8 moles of Cl2. So,

0.07203 moles of PCl5*(8 moles of Cl2/2 moles of PCl5)=0.28812 moles of Cl2,

0.28812 moles of Cl2*(70.906 g/moles)=20 g or 0.020kg of Cl2

i got 6.96g of chlorine gas

am i right?

I obtained 20.46 g Cl2. There are 2 significant figures in 0.15 kg so 20.46 rounded to 2 places is 20. g.

I don't still get the answer to the question. Please explain more.

You post your work and I'll find the error.

Anonymous is right on.Note that the coefficients are double what they should be (a boo boo I made when I first posted) but that doesn't change anything.

I have seen my mistake. Thanks.

If 10g of phosphorus is made to react with 15g of chlorine gas, calculate the percentage yield if 5.5g of phosphorus pentachloride was experimentally produced.

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