# Physics

You have been hired to help improve the material movement system at a manufacturing plant. Boxes containing 16 kg of tomato sauce in glass jars must slide from rest down a frictionless roller ramp to the loading dock, but they must not accelerate at a rate that exceeds 2.4 m/s^2 because of safety concerns.

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1. Part A: What is the maximum angle of inclination of the ramp?

Part B: If the vertical distance the ramp must span is 1.4 m, with what speed will the boxes exit the bottom of the ramp?

Part C: What is the normal force on a box as it moves down the ramp?

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posted by Mike
2. If g= 9.81/s^2
then m g sin A = 9.81 m sin A = m a = m * 2.2
or in other words sin A = 2.2 / 9.81

kinetic energy at bottom = potential at top (there is no friction)
(1/2) v^2 = g h
v = sqrt (2 * 9.81 * 1.4)

normal force = m g cos A

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posted by Damon
3. typo, use 2.4 not 2.2
sin A = 2.4/9.81

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posted by Damon

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