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Convert the complex no. In polar form : 1i rcosΘ =1 rsinΘ=1 r=√a2+b2 r=√(1)2+(1)2 r=√2 TanΘ=b/a =1/1 =1 After all this what i have to do to find out value of Θ? Please help me.. For polar form, =r(cosΘ+isinΘ)
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convert the equation y^2 = 2x x^2 into polar form. convert the equation r = 2tan(theta) into rectangular form. I'm not really sure what either of these mean. I vaguely understand polar coordinates, but I'm not sure how to convert
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5x+3y=8 convert each rectangular equation to polar form Convert each polar equation to rectangular form: a r=9cos0 b r=5 c rsq= cos 20 d r= 3____ 3+sin 0 Is this a test?
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convert the polar equation to rectangular form. 1.) r sec(theta) = 3 2.) r = 4 cos(theta)  4 sin(theta) convert from rectangular equation to polar form. 1.) x^2 + (y1)^2 = 1 2.) (x1)^2 + (y+4)^2 = 17
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convert the polar equation to rectangular form. 1.) r sec(theta) = 3 2.) r = 4 cos(theta)  4 sin(theta) convert from rectangular equation to polar form. 1.) x^2 + (y1)^2 = 1 2.) (x1)^2 + (y+4)^2 = 17
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Precalculus; urgent ! Please help !
1.Graph the polar equation r=32sin(theta) 2. Find the polar coordinates of 6 radical 3,6 for r > 0. 3. Find the rectangular coordinates of (7, 30°). 4. Write the rectangular equation in polar form. (x – 4)2 + y2 = 16 5. Write
asked by Becca on February 26, 2013 
Calculus please help !
1.Graph the polar equation r=32sin(theta) 2. Find the polar coordinates of 6 radical 3,6 for r > 0. 3. Find the rectangular coordinates of (7, 30°). 4. Write the rectangular equation in polar form. (x – 4)2 + y2 = 16 5. Write
asked by Becca on February 26, 2013 
Math ! Please Help !
1.Graph the polar equation r=32sin(theta) 2. Find the polar coordinates of 6 radical 3,6 for r > 0. 3. Find the rectangular coordinates of (7, 30°). 4. Write the rectangular equation in polar form. (x – 4)2 + y2 = 16 5. Write
asked by Becca on February 26, 2013 
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for what value of r=4sinè have vertical tangent? In polar coordinates? Theta=90 deg is vertical. I do not know if you know how to differentiate polar coordinate equations so I changed your equation from polar to rectangular form,
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PreCalculus
Convert the equation y=5 to polar form.
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