It takes Marty 11/4 hours to get ready for school. If 1/5 of that time is used to shower and 1/3 of that time is used to eat breakfast, how long does it take him to shower and eat breakfast?
T = (1/5 + 1/3) * 11/4 = (3/15 + 5/15) * 11/4 = 8/15 * 11/4 = 88/60 = 1.5 h.
To find out how long it takes Marty to shower and eat breakfast, we need to calculate 1/5 of 11/4 hours for showering and 1/3 of 11/4 hours for eating breakfast.
First, let's calculate 1/5 of 11/4 hours for showering:
(1/5) x (11/4) = (1 x 11) / (5 x 4) = 11/20 hours
Then, let's calculate 1/3 of 11/4 hours for eating breakfast:
(1/3) x (11/4) = (1 x 11) / (3 x 4) = 11/12 hours
Therefore, it takes Marty 11/20 hours to shower and 11/12 hours to eat breakfast.
To find out how long it takes Marty to shower and eat breakfast, we need to determine the portions of time he spends on each activity individually and then add them together.
First, we calculate the time Marty spends showering, which is 1/5 of the total time it takes him to get ready. To do this, we multiply 11/4 by 1/5:
(11/4) * (1/5) = 11/20
So, Marty spends 11/20 hours on showering.
Next, we calculate the time Marty spends eating breakfast, which is 1/3 of the total time it takes him to get ready. To do this, we multiply 11/4 by 1/3:
(11/4) * (1/3) = 11/12
Therefore, Marty spends 11/12 hours on eating breakfast.
Finally, to determine the total time it takes him to shower and eat breakfast, we add the times together:
11/20 + 11/12
To add these fractions, we need to find a common denominator, which in this case is 60:
11/20 + 11/12 = (33/60) + (55/60) = 88/60
We can simplify this fraction by dividing both the numerator and denominator by the greatest common divisor, which is 4:
88/60 = (22/15)
Therefore, it takes Marty approximately 1 and 7/15 hours, or 1 hour and 28 minutes, to shower and eat breakfast.