Math

The sum of two integers is 12. Rhe difference in their reciprocal is 2/9. Determine the 2 integers.

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  1. one number --- x
    the other ----- y
    x+y=12 -----> x = 12-y
    x - 1/y = 2/9
    12-y - 1/y = 2/9
    multiply by 9y
    108y - 9y^2 - 9 = 2y
    9y^2 - 106y + 9 = 0
    solve the quadratic, does not come out nice

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    posted by Reiny
  2. If y is the larger number
    x+y = 12
    1/x - 1/y = 2/9
    1/x- 1/(12-x) = 2/9
    Now it ends much nicer

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    posted by oobleck
  3. thanks, oobleck
    I should really read the questions more carefully.

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    posted by Reiny

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