Calculus
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Calculus
Which of the following integrals can be integrated using partial fractions using linear factors with real coefficients? a) integral 1/(x^41) dx b) integral (3x+1)/(x^2+6x+8) dx c) integral x^2/(x^2+4) d) None of these
asked by Alice on April 7, 2019 
Calc easy
Having trouble getting the correct solution. The integral of “x squared” in the numerator and “x squared plus x minus 6” in the denominator. S X2 / (X2 + x – 6) dx Thanks! That's a messy one. According to my table of
asked by Ang on February 23, 2007 
Calculus II
Express the integrated as a sum of partial fractions and evaluate the integral 3x2+x+9/(x2+5)(x6)
asked by Rosali on June 5, 2017 
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Calculate the integrals by partial fractions and using the indicated substitution. Show the results you get are the same. dx/1x^2; substitution x= sin pheta I understand how to do the partial fraction part, but not the second
asked by Jessica on February 25, 2008 
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Evaluate the integral by first performing long division on the integrated and then writing the proper fraction as a sum of partial fractions. x^4/x^29
asked by Rosali on June 5, 2017 
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Help me on this one :( Express y= (73xx^2)/[((1x)^2)(2+x)] in partial fractions. Hence, prove that if x^3 and higher powers of x may be neglected, then y=(1/8)(28+30x+41x^2) I did the first part of expressing it in partial
asked by Keira on March 3, 2010 
calc II
Express the integrals as the sum of partial fractions and evaluate the integral: (integral of) (x^2)dx/(x1)(x^2 +2x+1) My work: The above integral is equal to x^2dx/(x+1)^2 (A/x1) + (B/x+1) + (Cx+D)/(x+1)^2 = x^2 A(x+1)^2 +
asked by Jenna on December 6, 2009 
CALC 2  Partial Functions!!
How do I solve Integral of 7/(16x^2) I know I must break down (16x^2) into (x+4)(x+4), but after I do that what is next? Using the method of partial fractions, convince yourself that 7/(16x^2)= (7/8)*[1/(4+x) + 1/(4x)] The
asked by Ace on June 13, 2007 
Calc II
Perform long division on the integrand, write the proper fraction as a sum of partial fractions, and evaluate the integral: (integral of) 2y^4dy/y^3  y^2 + y  1 After long divison I get: (integral of)2ydy + 2(integral of)dy +
asked by Jenna on December 6, 2009 
Calculus  Integration
I came across this problem in my homework, and I was wondering if partial fractions would be rational for this problem. Int [(2x)/((x^2)^2)]dx If I don't use partial fractions, what would I use?
asked by Sean on May 9, 2008