I have to use the discriminate to determine the number of answers for the following equation, but my textbook never showed me how to find the discriminate for an equation like this. Could someone show me how to find the discriminate? 9x^2 + 6× = -1
So does that mean the discriminate would be 0? I looked back in my notebook and it seems that I did the problem and I got an answer of 36 by doing 6^2 - 4(0). Is that right?
Yes.
This is correct.
9 x² + 6 x = - 1
Add 1 to both sides
9 x² + 6 x + 1 = - 1 + 1
9 x² + 6 x + 1 = 0
D = b² - 4 a c
In this case:
a = 9 , b = 6 , c = 1
D = b² - 4 a c
D = 6² - 4 ∙ 9 ∙ 1 = 36 - 36 = 0
6² - 4 ∙ 0 is 36 but that is not discriminate.
y = 9 x² + 6 x + 1
a = 9 , b = 6 , c = 1
D = b² - 4 a c = 6² - 4 ∙ 9 ∙ 1 = 36 - 36 = 0
Ohhh. So the discriminate would be zero. And since it's zero, that means that I would get the answer by doing ×= -b/2a
So ×= -6/2(9)= -1/3. Which means this problem only has one solution. Is this correct?
discriminant.
It is used to discriminate
To determine the discriminant of a quadratic equation, you need to consider the equation in the standard form: ax^2 + bx + c = 0. In your case, the equation is 9x^2 + 6x = -1. To find the discriminant, you need to identify the values of a, b, and c.
Comparing this equation to the standard form, you can see that a = 9, b = 6, and c = -1. The discriminant (denoted as Δ) is calculated using the formula: Δ = b^2 - 4ac.
Substituting the values from the equation, you can now find the discriminant:
Δ = (6)^2 - 4(9)(-1)
Δ = 36 + 36
Δ = 72
Therefore, the discriminant in the equation 9x^2 + 6x = -1 is 72.