A sample of aluminium has a mass of 6.3g, calculate 1.the number of mole of aluminium present.2.the number of atoms of aluminium take(AL=27)

10 answers

1. moles = mass / atomic mass = 6.3 / 27

2. atoms = moles * Avogadro's number = moles * 6.02E23

The correct answer

Mole =mass/molar mass=6.3/13

Mole of Al present=0.233

Mass/molar mass =6.3/13

answer

1.0.233

2.1.40266-10^23

GLAIIE

mole present = 0.23

0.23mole

Did you know?

Did you know that you can calculate the number of moles and atoms present in a sample of a substance using its mass and atomic mass? For example, if a sample of aluminum has a mass of 6.3g, we can calculate: 1. The number of moles of aluminum present by dividing the mass of aluminum by its atomic mass. The atomic mass of aluminum (Al) is 27 g/mol. Therefore, the number of moles of aluminum in the sample is 6.3g / 27 g/mol = 0.233 moles. 2. The number of atoms of aluminum present by multiplying the number of moles by Avogadro's number, which is approximately 6.022 x 10^23. Therefore, the number of atoms of aluminum in the sample is 0.233 moles x 6.022 x 10^23 atoms/mol = 1.4 x 10^23 atoms. Understanding the concept of moles and Avogadro's number allows scientists to relate the macroscopic world of mass and grams to the microscopic world of atoms and particles, providing valuable insights into the composition and properties of various substances.