Calculate the heat change in kilocalories for condensation of 6.5
kg
of steam at 100
∘
C
.
q = mass x delta H
I think dH is 540 calories/gram
Post your work if you have more questions.
That is correct, DrBob ... If ya need it in joules/gram => ΔHᵥ = 2300 j/g
To calculate the heat change in kilocalories for the condensation of steam, we need to use the formula:
Q = m * L
Where:
Q is the heat change in calories
m is the mass of the substance
L is the latent heat
First, let's convert the mass of steam from kilograms to grams:
Mass of steam in grams = 6.5 kg * 1000 g/kg
Mass of steam in grams = 6500 g
Next, we need to determine the latent heat of steam at 100 degrees Celsius. The latent heat of steam is approximately 540 calories/gram.
Now we can calculate the heat change:
Q = 6500 g * 540 calories/gram
Q = 3,510,000 calories
Lastly, we can convert the heat change from calories to kilocalories:
Heat change in kilocalories = 3,510,000 calories / 1000 calories/kilocalorie
Heat change in kilocalories = 3,510 kilocalories
Therefore, the heat change in kilocalories for the condensation of 6.5 kg of steam at 100 degrees Celsius is 3,510 kilocalories.
To calculate the heat change in kilocalories for the condensation of steam, we need to understand the concept of specific heat and latent heat.
Specific heat is the amount of heat energy required to raise the temperature of 1 kg of a substance by 1 degree Celsius. For water, the specific heat is approximately 1 calorie/gram °C.
Latent heat is the energy required to change the state of a substance without changing its temperature. For water, the latent heat of vaporization (the heat absorbed when steam condenses into water) is approximately 540 calories/gram.
Given that we have 6.5 kg of steam at 100 degrees Celsius, we need to calculate the heat change when it condenses into water at 100 degrees Celsius.
First, we need to calculate the heat change to cool the steam from 100 degrees Celsius to 100 degrees Celsius. Since the temperature doesn't change, there is no heat change in this step.
Next, we need to calculate the heat change for the condensation process itself.
Heat change (in kilocalories) = Mass of steam (in kg) * Latent heat of vaporization (in calories/gram) / 1000
Let's substitute the values into the formula:
Heat change = 6.5 kg * 540 calories/gram / 1000
Heat change = 3.51 kilocalories
Therefore, the heat change for the condensation of 6.5 kg of steam at 100 degrees Celsius is 3.51 kilocalories.