chemistry

30cm^3 of a mixture of methane and ethyne require 70cm^3 of oxygen for complete combustion. Calculate the composition of the mixture

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asked by emilie
  1. This is a problem with two unknowns (at least the way I'm solving it) so it requires two equations and you solve them simultaneously.
    Write and balance the equations.
    CH4 + 2O2 ==> CO2 + 2H2O
    2C2H2 + 5O2 ==> 4CO2 + 2H2O

    Let X = cc of CH4
    and Y = cc of C2H2
    ----------------------------

    equation 1 is X + Y = 30 cc
    equation 2 is cc oxygen in tems of X and Y
    (2X) is cc O2 in terms of X for combustion of CH4 and
    (5Y/2) is cc O2 in terms of Y for combustion of C2H2. Put those together to get equation 2 which is
    2X + 5Y/2 = 70 cc..........equation 2
    X + Y = 30 cc ..............equation 1
    Solve for X and Y.
    The problem doesn't say how it wants the composition; usually this is done as a percent so
    (X/70)*100 = %CH4
    (Y/70)*100 = %C2H2
    Post your work if you get stuck.

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