Find the distance between the two points. Round to the nearest tenth, if necessary.
(-3, 16) and (15, -8)
To find the distance between two points, we can use the distance formula:
Distance = √((x2 - x1)^2 + (y2 - y1)^2)
For the given points (-3, 16) and (15, -8), we can substitute the coordinates into the formula:
Distance = √((15 - (-3))^2 + (-8 - 16)^2)
Simplifying further:
Distance = √((15 + 3)^2 + (-8 - 16)^2)
Distance = √((18)^2 + (-24)^2)
Distance = √(324 + 576)
Distance = √(900)
Distance = 30
Therefore, the distance between the two points (-3, 16) and (15, -8) is 30 units.
To find the distance between two points in a coordinate plane, we can use the distance formula:
Distance = √((x2 - x1)^2 + (y2 - y1)^2)
Given the two points (-3, 16) and (15, -8), we can assign the values as follows:
x1 = -3, y1 = 16
x2 = 15, y2 = -8
Plugging these values into the distance formula, we get:
Distance = √((15 - (-3))^2 + (-8 - 16)^2)
= √(18^2 + (-24)^2)
= √(324 + 576)
= √(900)
= 30
Therefore, the distance between the two points (-3, 16) and (15, -8) is 30.
draw a sketch and use the Pythagorean theorem
BIG HINT ... it's a 3-4-5 triangle
(-3, 16), (15, -8).
X = (15-(-3)) = 18.
Y = (-8-16) = -24.
d = sqrt(X^2 + Y^2) =