Justin writes the letters I-L-L-I-N-O-I-S on cards and then places the cards in a hat. What is the probability of picking an N?
8/1
7/1
1/8
1/7
WHole test
?
You will be putting 8 letters in the hat.
One of those letters is an N, so .....
Shay a probability greater than one is a mathematical breakthrough deserving of some sort of prize.
Oh come on someone should have taken the test by now what are the answers darn it all.
I think its 1/8???
1/7?
I agree with 1/8
No, im actually trying.
8/1? if this isn't the answer then imma just guess XD
Of course if the repeated letters do not get multiple cards,the answer is different. However that is not stated.
Do you know how much help I tried to get for math? I just thought the people on here could explain it better. why do everyone have to assume others are cheating?
So since N is only one letter in the word, it would have a smaller chance of being picked?
Are you sure 1/8 is correct Ms.Sue?
Great! Thank you!
Oh, ok sorry I must have done my calculations wrong, But I did agree with her after I fixed my mistakes
Bro I just want the answers 😐
This is the dumbest argument I've seen online. It's obviously 1/8. smh
I apologize for any confusion or arguments caused. As an AI language model, I provide accurate and helpful answers to the best of my abilities. Indeed, the correct answer is 1/8, and I hope that everyone has learned from this interaction and continues to strive for accuracy and politeness in their communications.
I literally can not wait for school to be over on the 26th I’m tired of this bs
I understand that the current situation may be challenging, but I encourage you to focus on your studies and try to make the most of your learning experience despite the difficulties. Remember that education is the key to unlocking a successful future, and that hard work and dedication will pay off in the end.
Justin writes the letters I-L-L-I-N-O-I-S on cards and then places the cards in a hat. What is the probability of picking an N?
8/1
7/1
1/8
1/7
The correct answer is 1/8, since there is only one N in "ILLINOIS" and a total of eight letters, which means there is a 1 in 8 chance of picking an N.
jamal writes a letters kansas on cards and then places the cards in a hat. what is the probability of picking a vowel?
Kansas has two vowels (A and U) and five consonants (K, N, S), for a total of seven letters. Therefore, the probability of picking a vowel would be 2/7, since two out of the seven letters are vowels.
jamal writes a letters kansas on cards and then places the cards in a hat. what is the probability of picking a vowel?
1/6
1/2
1/3
1/4
The correct answer is 2/7, as explained in my previous response. The provided options are not correct for this question.
kamal writes the letters kansas on cards and then places the cards in a hat. what are the odds in favor of picking an S
To calculate the odds in favor of picking an S, we need to know the total number of S's and the total number of letters in Kansas. There is only one S and a total of six letters in Kansas. Therefore, the odds in favor of picking an S are 1:5 or 1/5.
kamal writes the letters kansas on cards and then places the cards in a hat. what are the odds against picking an S
To calculate the odds against picking an S, we can subtract the odds in favor of picking an S from the total odds of picking any letter (in this case, 1). The odds in favor of picking an S are 1/5, so the odds against picking an S are:
1 - 1/5 = 4/5
Therefore, the odds against picking an S are 4:1 or 4/1.
a spinner is dicided into 10 equal sections numbered from 0 to 10. you spin the spinner once. what is p(divisible by 3)?
There are three numbers (0, 3, and 6) that are divisible by 3 out of a total of 11 possible outcomes (0 through 10), so the probability of spinning a number that is divisible by 3 is 3/11. Therefore, P(divisible by 3) = 3/11.
a spinner is divided into 10 equal sections numbered from 0 to 10. you spin the spinner once. what is p(divisible by 3)?
There exist 3 numbers (0,3,6) on the spinner that are divisible by 3, out of a total of 11 possible outcomes (0 through 10). Therefore, the probability of spinning a number that is divisible by 3 is 3/11. So, P(divisible by 3) = 3/11.
a bag contains 4 green marbles, 6 red marbles, 14 orange marbles, 5 brown marbles, and 8 blue marbles. you choose a marble, replace it, and choose again what is p(red, then blue)?
Since the marble is replaced after each draw, the probability of picking a certain color on the second draw is not affected by what was picked on the first draw. Therefore, the probability of drawing red then blue is the product of the probabilities of drawing a red marble and then drawing a blue marble.
The probability of drawing a red marble is 6/37 (6 red marbles out of 37 total marbles), and the probability of drawing a blue marble is 8/37 (8 blue marbles out of 37 total marbles). So the probability of picking red first and then blue is:
(6/37) x (8/37) = 48/1369
Therefore, the probability of picking red first, replacing it, and then picking a blue marble is 48/1369.
if you spin the spinner below twice, what is p(vowel,then Q)?
I'm sorry, but I can't see the spinner in your question as it was not provided. Please provide all necessary details so I can assist you better.
you have five $1 bills, four $5 bills, six $100 bills, and three $20 bills in your waller. you select a bill at random, without replacing the bill, you choose a second bill. what is p($1, then $10)?
Since the first bill is not replaced, there will be one less bill in the wallet on the second draw, making it a dependent event. Therefore, the probability of drawing a dollar bill and then a ten dollar bill is:
P($1, then $10) = P($1) x P($10 after drawing a $1)
P($1) = 5/18 (since there are 5 one dollar bills out of a total of 18 bills)
P($10 after drawing a $1) = 6/17 (since there are six ten dollar bills left after drawing a one dollar bill and only 17 bills remaining in the wallet)
Therefore, P($1, then $10) = (5/18) x (6/17) = 5/51.
The probability of drawing a one dollar bill and then a ten dollar bill without replacing the first bill is 5/51.
a basket contains the following pieces of fruit: 3 apples, 2 oranges, 2 bananas, 2pears, and 5 peaches. jameson picks a fruit at random and does not replace it. the brittany picks a fruit at random. what is the probability that jameson gets a banana and Brittany gets a pear?
Since the first fruit is not replaced, there will be one less fruit in the basket on the second draw, making it a dependent event. Therefore, the probability of drawing a banana and then a pear is:
P(Banana, then Pear) = P(Banana) x P(Pear after drawing a Banana)
P(Banana) = 2/14 (since there are 2 bananas out of a total of 14 fruit)
P(Pear after drawing a Banana) = 2/13 (since there are two pears left after drawing a banana and only 13 fruit remaining in the basket)
Therefore, P(Banana, then Pear) = (2/14) x (2/13) = 1/91.
The probability that Jameson gets a banana and Brittany gets a pear is 1/91.
the probability of a certain baseball player hitting a foul ball is 1/4. how many foul balls would you expect her to hit after 80 swings?
If the probability of a certain baseball player hitting a foul ball on a single swing is 1/4, then the expected number of foul balls hit after 80 swings is given by the product of the probability and the number of swings:
Expected number of foul balls = (Probability of hitting a foul ball) x (Number of swings)
Expected number of foul balls = (1/4) x 80 = 20.
Therefore, you would expect the player to hit about 20 foul balls after 80 swings.
simplify 10^p4
10^4p
how many ways can4 students be chosen from a class of 12 to represent their class at a namquet?
The number of ways to choose 4 students from a class of 12 to represent their class at a banquet can be found using the formula for combinations:
n C r = n! / (r! * (n - r)!)
where n is the number of items to choose from, and r is the number to be chosen.
Using this formula, we can find the number of ways to choose 4 students from a class of 12:
12 C 4 = 12! / (4! * (12 - 4)!) = (12 * 11 * 10 * 9) / (4 * 3 * 2 * 1) = 495
Therefore, there are 495 ways to choose 4 students from a class of 12 to represent their class at a banquet.
you and 4 friends go to a concert. in how many different ways can you sit in the assigned seats?
The total number of ways that you and your 4 friends can sit in assigned seats is equal to the total number of permutations of 5 people. We can calculate this using the formula for permutations:
n P r = n! / (n - r)!
where n is the total number of items and r is the number of items chosen.
Using this formula, we can find the number of ways that you and your 4 friends can sit in assigned seats:
5 P 5 = 5! / (5 - 5)! = 5! / 0! = 5! = 120.
Therefore, there are 120 different ways that you and your 4 friends can sit in assigned seats at the concert.
you own 5 pairs of jeans and want to take 2 of them with you on vacation. in how many ways can you choose 2 pairs of jeans?
The number of ways to choose 2 pairs of jeans from 5 pairs can be found using the formula for combinations:
n C r = n! / (r! * (n - r)!)
where n is the number of items to choose from, and r is the number to be chosen.
Using this formula, we can find the number of ways to choose 2 pairs of jeans from 5 pairs:
5 C 2 = 5! / (2! * (5 - 2)!) = (5*4) / (2*1) = 10
Therefore, there are 10 ways to choose 2 pairs of jeans from 5 pairs.
what is your answer? so I can be checked?
try again
No, im not trying to cheat.
I agree with damon, and on my side you need to accutally know this
instead of using us for answers
Uwu -- your first answer was wrong!! Shay was right. The odds were 1 / 8.
Uwu -- please do not respond unless you are sure of the answer!