1.Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
Image is a triangle with one side labeled as the 3 point 6 feet diameter of a semi-circle. The vertex opposite the semi-circle side is bi-sected by a horizontal line labeled 4 point 8 feet between the semi-circle diameter side and the opposing triangle.
Find the area of the irregular figure (use 3.14 for pi). Show your work. Round to the nearest tenth.
Do you mean that the figure consists of a triangle and a semi-circle which share a common side of 3.6, and the altitude of the triangle is 4.8? So it looks kind of like a sno-cone?
If so, then the area is
1/2 πr^2 + 1/2 bh = 1/2 π * 3.6^2 + 1/2 * 3.6 * 4.8 = 29
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I don't see anonymous's answer...
Please someone help im in need
Man y'all suck😐 jk but seriously no one knows the answer
you guys are useless
The area of a triangle is base times height divided by two. Therefore, 4.8 times 3.6 = 8.64. The radius of the half circle is 1.8. So, 1.8 times 3.14 divided by 2 = 5.0868. Then, add both areas together to get the total area. 8.64+5.0868= 13.7268. After being rounded to the nearest tenth, the answer is 13.7.
Hope this helps! :D
i need help know
Plz help, i know there is a hero out there that can help
Impressive very nice, Lets see Paul Allen's answers.
connexus student a weirdo
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Ok I have a different question and I can't see where 2 put it, so i am putting it here. Enter your answer and show all the steps that you use to solve this problem in the space provided.
A cone with a diameter of 8 inches and a height of 7 inches.
Find the surface area of the cone. Use 3.14 for
π
.
Plz help
I NEED HELP WITH THIS
What is the formula 4 surface area 4 a cone?
The formula to calculate the total surface area of the cone is: TSA of cone = πr2 + πrl = πr(l+r) square units.
:)