Calculate the mole fraction of Benzene in a solution containing 30% by mass of Benzene in CCl4?
Let's assume we have 100 g of 30% benzene in CCl4. Then we have 30 g benzene and 70 g CCl4.
mols benzene = 30 g/molar mass benzene = ?
mol CCl4 = 70 g/molar mass CCl4.
Xbenzene = mols benzene/total mols = ?
To calculate the mole fraction of Benzene in a solution, you need to know the mass of Benzene and the mass of the solvent (CCl4 in this case). Then, you can use the following formula to find the mole fraction:
Mole Fraction = (moles of Benzene) / (moles of Benzene + moles of CCl4)
To begin, let's assume we have 100 grams of the solution. From the given information, we know that 30% of this mass is Benzene.
Mass of Benzene = 30% of 100g = 0.3 * 100g = 30g
Now, we need to find the moles of Benzene and CCl4. To do this, we can use the molar mass of each substance.
The molar mass of Benzene (C6H6) is 78.11 g/mol, and the molar mass of CCl4 is 153.82 g/mol.
Moles of Benzene = Mass of Benzene / Molar mass of Benzene
= 30g / 78.11 g/mol
Moles of Benzene = 0.384 mol
Since we started with 100 grams of the solution, we can find the mass of CCl4 by subtracting the mass of Benzene from the total mass.
Mass of CCl4 = Mass of the solution – Mass of Benzene
= 100g – 30g
= 70g
Moles of CCl4 = Mass of CCl4 / Molar mass of CCl4
= 70g / 153.82 g/mol
Moles of CCl4 = 0.455 mol
Now that we have the moles of Benzene and CCl4, we can calculate the mole fraction:
Mole Fraction = Moles of Benzene / (Moles of Benzene + Moles of CCl4)
= 0.384 mol / (0.384 mol + 0.455 mol)
= 0.384 mol / 0.839 mol
Mole Fraction ≈ 0.458
Therefore, the mole fraction of Benzene in the solution is approximately 0.458.