volume of right circular cones total surface area is 550dm3. its radius of base is 5dm. find its total surface area
the base has area 25π dm^2
so, the height can be found using
πr^2h = 550
25πh = 550
h = 7
So, the slant height is s = √(2.5^2+7^2) = 7.43
That makes the lateral area 2πrs = 233.5
Now just add the base to the lateral area...
To find the total surface area of a right circular cone, we need two measurements: the radius of the base (r) and the slant height (l).
Since we are given the radius of the base (r) as 5 dm, we need to find the slant height (l) to calculate the total surface area.
To find the slant height, we can use the Pythagorean theorem. In a right triangle with the height (h), slant height (l), and radius (r), the Pythagorean theorem states that:
l^2 = h^2 + r^2
In this case, we are given the value of the radius (r) as 5 dm. Rearranging the equation, we get:
h^2 = l^2 - r^2
Now, let's calculate the slant height (l):
l = square root of (h^2 + r^2)
Since the problem statement does not provide the height (h), we cannot directly calculate the slant height (l) and therefore cannot find the total surface area.
Please provide the height of the cone in order for us to proceed with the calculation.