Which set of ordered pairs demonstrates a function?
A
(-2, -4), (-1, -2), (1, 2), (2, 4)
B
(-2, 4), (1, 2), (1, -2), (2, -4)
C
(-2, 4), (-1, 2), (-1, 2), (-2, -4)
D
(-2, 4), (-1, 2), (-1, -2), (-2, -4)
i got b, it it right ?
But is there an actual answer that can tell me if A, B, C, or D is right?
If in any set, you can find 2 or more points that lie on the same vertical,
then it is NOT a function, that is, the same value of x yields 2 or more different
values of y, you don't have a function.
e.g. D is definitely not a function. You have (-2,4) and (-2,-4) , the same x of -2 giving you a y value of 4 and -4.
So look them over again, and re-think your answer.
egbfbggss
0_0_0_0_0_0_0_0_0_0_0_0
Use the tables to answer the question.
Table A
Table B
Input
Output
Input
Output
-5
2
-5
2
-8
5
-8
5
-5
8
-11
2
Which BEST describes the tables?
No, option B does not demonstrate a function. A set of ordered pairs represents a function if no two different input values are paired with the same output value. In option B, the input value of 1 is paired with both the output values of 2 and -2, violating the rule for a function.
The set of ordered pairs that demonstrates a function is option A. Each input value is paired with a unique output value, hence satisfying the definition of a function.