If the volume of a gas @ STP is 300.0 ml, what is its volume at 25.0 C, assuming constant
pressure?
the volume is directly related to the absolute (Kelvin) temperature
327ml
To find the volume of a gas at a different temperature, you can use the combined gas law equation, which relates the initial and final volume, temperature, and pressure of a gas. The equation is:
(V1/T1) = (V2/T2)
Where:
V1 and T1 are the initial volume and temperature
V2 and T2 are the final volume and temperature
In this case, we know:
V1 = 300.0 mL (initial volume)
T1 = 0°C or 273.15 K (initial temperature at STP)
T2 = 25°C or 298.15 K (final temperature)
Let's plug in the values into the equation and solve for V2, the final volume:
(V1/T1) = (V2/T2)
(300.0 mL / 273.15 K) = (V2 / 298.15 K)
To solve for V2, we need to cross multiply and then divide:
V2 = (V1/T1) * T2
V2 = (300.0 mL / 273.15 K) * 298.15 K
Calculating this expression will give us the final volume of the gas at 25.0°C.
Note: The calculation assumes constant pressure.