Construct triangle ABC in which AB is 7cm AC is 9.5cm and is 120.measure BC.
The drawing and the calculation that's what I want
Construct triangle ABC in which AB is 7cm AC is 9.5cm and is 120.measure BC.
so, did you do the construction, and measure BC?
what did you get?
If angle A is 120 then you should get
BC^2 = 7^2 + 9.5^2 - 2*7*9.5*cos120°
BC ≈ 14.3
Construct ∆ABC such that /AB/=6cm, /AC/=8.5 cm and BAC = 120°
Kutta hai to kutta
It's the pictures of the caculations I want
It helps students
Show me the answer
To construct triangle ABC, follow these steps:
1. Draw a line segment AB of length 7 cm.
2. From point A, draw an arc with a radius of 9.5 cm. This arc should intersect the line AB at some point, which we will call C.
3. From point C, draw an arc with a radius of 7 cm. This arc should intersect the previous arc at some point, which we will call B.
4. Finally, draw the line segment BC to complete the triangle ABC.
To measure the length of BC:
1. Use a ruler to measure the distance between points B and C. This will give you the length of BC.
Keep in mind that the angle measurement of 120 degrees mentioned in the question does not affect the construction of the triangle or the measurement of length BC.