Physics

When a high-speed passenger train traveling at 161 km/h rounds a bend,the engineer is shocked to see that a locomotive has improperly entered onto the track from a siding
and is a distance(D)= 676m ahead.The locomotive is moving at 29.0 km/h.The engineer of the high-speed train immediately applies the brakes.What must be the magnitude of the
resulting constant deceleration if a collision is to be just avoided

Solve

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  1. 161 km/h = 44.722 m/s
    29 km/hr = 8.056 m/s
    Now just solve the usual equations.
    The distance traveled by the train must equal the distance traveled by the locomotive, plus the 676m separating them at first:
    44.722 + at = 0
    44.722t + 1/2 at^2 = 676 + 8.056t
    a = -0.946 m/s^2

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