The floors of a twenty storey building is spaced 2,2 m apart.An elevator stars at 08h00 on ground level with persons A and B .They go up to floor 17 and return immediately to floor 14 where A get out.B return to ground levele where he arrived at 08h03.what is the total distance traveled by persons A and B ?2. what is the average speed attained by the elevator? 3.what time will it take for person to go from ground level to the top of the building?
Is this in Europe, where floor 1 is one up from the ground floor? If so,
1. A and B went up 17 then down 3, or 20 floors times 2,2 m/floor
2. Assuming zero time at each stop, then the elevator went 34 floors in 3 minutes, or 34/3 floor/min.
3. 20 floors would thus take 20/34 * 3 min
1. The total distance traveled by persons A and B can be calculated as follows:
- From ground level (0) to floor 17: 17 - 0 = 17 floors
- From floor 17 to floor 14: 17 - 14 = 3 floors
- From floor 14 to ground level: 14 - 0 = 14 floors
Total distance traveled by persons A and B = 17 + 3 + 14 = 34 floors
2. The average speed attained by the elevator depends on the time taken to travel the total distance. We know that person B arrived at ground level at 08h03. Let's assume it took them 3 minutes to travel the total distance. We can calculate the average speed using the formula:
Average Speed = Total Distance / Time Taken
Average Speed = 34 floors / 3 minutes = 11.33 floors/minute
Therefore, the average speed attained by the elevator is approximately 11.33 floors per minute.
3. Since person B arrived at ground level at 08h03 after going from floor 14 to the ground, we know that it took them 3 minutes to cover 14 floors. Therefore, we can assume that for a 20-floor building, it would take approximately (3 minutes / 14 floors) * 20 floors = 4.29 minutes to travel from the ground level to the top of the building.
However, it is important to note that this calculation assumes a constant speed throughout the elevator journey, which may not be accurate in real life scenarios.
To find the total distance traveled by persons A and B, we need to calculate the distance from the ground level to floor 17, then from floor 17 to floor 14, and finally from floor 14 back to the ground level.
1. Distance from ground level to floor 17:
There are 17 floors, and each floor is spaced 2.2 meters apart. So the distance from the ground level to floor 17 is:
17 floors * 2.2 meters/floor = 37.4 meters
2. Distance from floor 17 to floor 14:
There are 17-14=3 floors between floor 17 and floor 14. So the distance from floor 17 to floor 14 is:
3 floors * 2.2 meters/floor = 6.6 meters
3. Distance from floor 14 back to the ground level:
There are 14 floors from floor 14 to the ground level. So the distance from floor 14 to the ground level is:
14 floors * 2.2 meters/floor = 30.8 meters
Therefore, the total distance traveled by persons A and B is:
37.4 meters + 6.6 meters + 30.8 meters = 74.8 meters
To calculate the average speed attained by the elevator, we need to know the time it took for persons A and B to travel the total distance.
In the question, it is given that person B arrived back at the ground level at 08h03. Therefore, the total time for the journey (including going up to floor 17 and returning to floor 14) is 3 minutes.
Average speed is calculated by dividing the total distance traveled by the total time taken.
Average speed = Total distance / Total time
Average speed = 74.8 meters / 3 minutes = 24.93 meters/minute (rounded to two decimal places)
To calculate the time it will take for a person to go from the ground level to the top of the building, we need to consider the total number of floors and the time it takes to travel one floor.
There are 20 floors in total.
From the question, we know that it took 3 minutes to go from the ground level to floor 14 (including the time to go up to floor 17 and returning to floor 14).
To find the time it will take to go from the ground level to the top of the building, we can use the following proportion:
Floor 14 time : Floor 17 time :: Floor 14 to ground level time : Time to go from ground level to top floor
Let's denote the time to go from the ground level to the top floor as T.
Therefore, we can set up the proportion:
3 minutes : T minutes :: 3 minutes : T + 3 minutes
Using cross-multiplication, we get:
3(T + 3) = 3T
Simplifying the equation:
3T + 9 = 3T
Subtracting 3T from both sides:
9 = 0
This is an inconsistent equation, which means there is no solution.
Therefore, we cannot determine the time it will take for a person to go from the ground level to the top of the building with the given information.
To find the total distance traveled by persons A and B, we need to determine the distance covered by each person and then add them together.
First, let's calculate the distance covered by person A. Since person A gets out on floor 14, we need to calculate the number of floors covered between the ground level and floor 14. Given that each floor is spaced 2.2 meters apart, we can find the distance by multiplying the number of floors by 2.2.
The number of floors between the ground level and floor 14 is 14 - 1 = 13 floors.
Distance covered by person A = 13 floors * 2.2 m/floor = 28.6 meters.
Second, let's calculate the distance covered by person B. Person B starts at ground level, goes up to floor 17, and then returns immediately to floor 14. This means person B covers the distance from ground level to floor 17 and then from floor 17 back to floor 14.
To calculate the distance covered by person B, we need to find the distance from the ground floor to floor 17 and then double it to account for the return trip.
The number of floors between the ground level and floor 17 is 17 - 1 = 16 floors.
Distance covered from ground to floor 17 = 16 floors * 2.2 m/floor = 35.2 meters.
Now, let's double the distance covered from ground to floor 17 to account for the return trip.
Total distance covered by person B = 2 * 35.2 meters = 70.4 meters.
Finally, to find the total distance traveled by persons A and B, we add the distances covered by each person.
Total distance = distance covered by person A + distance covered by person B
Total distance = 28.6 meters + 70.4 meters = 99 meters.
Therefore, the total distance traveled by persons A and B is 99 meters.
Now let's move on to the second question.
To find the average speed attained by the elevator, we need to divide the total distance traveled by the elevator by the time it took to cover that distance.
We know that person B arrives at ground level at 08h03, and the elevator started at 08h00. Therefore, the time taken by the elevator is 08h03 - 08h00 = 3 minutes.
Since we have to express the time in the same units as the distance, we need to convert 3 minutes to seconds. There are 60 seconds in a minute, so 3 minutes is equal to 3 minutes * 60 seconds/minute = 180 seconds.
Now, we can calculate the average speed attained by the elevator.
Average speed = Total distance / Time taken
Average speed = 99 meters / 180 seconds = 0.55 meters per second.
Therefore, the average speed attained by the elevator is 0.55 meters per second.
Moving on to the third question,
To find the time it will take for a person to go from ground level to the top of the building, assuming the top floor is floor 20, we need to calculate the number of floors between the ground level and floor 20 and then convert it into time.
The number of floors between the ground level and floor 20 is 20 - 1 = 19 floors.
Since each floor is spaced 2.2 meters apart, total distance covered = 19 floors * 2.2 meters/floor = 41.8 meters.
We can use the average speed attained by the elevator to find the time taken to cover this distance.
Time = Distance / Speed
Time = 41.8 meters / 0.55 meters per second = 76 seconds.
Therefore, it will take approximately 76 seconds for a person to go from the ground level to the top of the building.