Compute the following:
Let g(x)=3x, and h(x)=x^2+1.

Please show work & help me understand.

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  1. for any value of x, h(x)=x^2+1
    so, replace x with 3 and you have
    h(3) = 3^2+1

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    posted by oobleck
  2. That’s all to it?

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    posted by Charlie

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