two boxes have the same volume. One box has a base that is 2 inches by 2 inces. The other box has a base that is 4 inches by 4 inches. How many tines as tall is the box with the smaller base
h = Ht. of box with larger base.
(4*4)/(2*2) h = 4h = Ht. of box with smaller base.
4h/h = 4 Times as tall.
The box with the smalle base is 4 times taller than the other box.
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To determine how many times taller the box with the smaller base is, we need to compare the heights of the two boxes.
Let's call the height of the box with the smaller base "h" (in inches).
Since both boxes have the same volume, we can use the formula for the volume of a rectangular prism: V = base area × height.
For the first box with the base of 2 inches by 2 inches, the base area is 2 × 2 = 4 square inches.
For the second box with the base of 4 inches by 4 inches, the base area is 4 × 4 = 16 square inches.
Since the volumes of both boxes are the same, we can set up the following equation:
4 × h = 16 × h'
Where h' represents the height of the box with the larger base.
To find out how many times taller the box with the smaller base is, we can solve this equation for h' and divide h' by h:
h' = (4 × h) / 16
Now, let's find the value of h':
h' = (4 × h) / 16
h' = h / 4
Therefore, the box with the smaller base is 1/4 as tall as the box with the larger base.
Oliver is building a box kite. The frame of the kite has the dimensions shown. He covered the sides of the kite (but not the top and bottom) with 7200 cm2 of lightweight fabric. What is the volume inside the kite?
height of the 2 by 2 box ---- x
height of the 4 by 4 box ---- y
4*4*y = 2*2*x
16y = 4x
x = 4y
your conclusion ?