Further maths

If x is an acute angle, tanx =3/4,evaluate coax _sinx÷cosx+sinx

  1. 👍 0
  2. 👎 0
  3. 👁 20
asked by Emmanuel
  1. geez - take care with your expressions.
    divide top and bottom by cosx, Then you have
    (cosx-sinx)/(cosx+sinx) = (1-tanx)/(1+tanx) = (1/4)/(7/4) = 1/7
    extra credit: why does it matter that x is acute?

    1. 👍 0
    2. 👎 0
    posted by oobleck

Respond to this Question

First Name

Your Response

Similar Questions

  1. Trigonometry Check

    Simplify #3: [cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] = [cosx-((1)cosx-(0)sinx)sinx]/[cosx-((-1)cosx+(0)sinx)tanx] = [cosx-cosxsinx]/[cosx+cosxtanx] =

    asked by Anonymous on February 20, 2012
  2. maths - trigonometry

    I've asked about this same question before, and someone gave me the way to finish, which I understand to some extent. I need help figuring out what they did in the second step though. How they got to the third step from the

    asked by anonymous on June 19, 2010
  3. Maths

    If is a n acute angle and tanx=3 4 evaluate cosx-sinx cosx+sinx

    asked by Anonymous on May 27, 2013
  4. Maths

    If is a n acute angle and tanx=3 4 evaluate cosx-sinx cosx+sinx

    asked by Anonymous on May 27, 2013
  5. Maths

    If is a n acute angle and tanx=3 4 evaluate cosx-sinx cosx+sinx

    asked by Anonymous on May 27, 2013
  6. Maths

    If is a n acute angle and tanx=3 4 evaluate cosx-sinx cosx+sinx

    asked by Anonymous on May 27, 2013
  7. Pre-Calc

    Trigonometric Identities Prove: (tanx + secx -1)/(tanx - secx + 1)= tanx + secx My work so far: (sinx/cosx + 1/cosx + cosx/cosx)/(sinx/cos x - 1/cosx + cosx/cosx)= tanx + cosx (just working on the left side) ((sinx + 1 -

    asked by Dave on January 2, 2007
  8. Simplifying with Trigonometry Identities

    Hi, I am a senior in High School having a really difficult time with two problems. I have to prove using the trigonometric identities that they equal each other but I am having a really hard time trying to get them to equal each

    asked by amanda on March 7, 2007
  9. Calculus

    Q: If y=sinx/(1+tanx), find value of x not greater than pi, corresponding to maxima or minima value of y. I have proceeded thus- Equating dy/dx=0 we get{ (1+tanx)cosx-sinx.sec^2 x}/(1+tanx)^2=0……..(A) Or cosx+sinx=sinx.sec^2 x

    asked by MS on June 16, 2014
  10. Math

    Im really struggling with these proving identities problems can somebody please show me how to do these? I'm only aloud to manipulate one side of the equation and it has to equal the other side of the equation at the end Problem

    asked by Alycia on November 1, 2012
  11. Trigonometry.

    ( tanx/1-cotx )+ (cotx/1-tanx)= (1+secxcscx) Good one! Generally these are done by changing everything to sines and cosines, unless you see some obvious identities. Also generally, it is best to start with the more complicated

    asked by mo on April 18, 2007

More Similar Questions