Compute the electrical force between the following charges and state whether it is attractive or repulsive. Q1 = 3 microcoulombs and Q2 = -2 microcoulombs, separated by 12cm. use the following formula. k = 9x10^9 N*m^2/c^2.
The formula is F = k*(Q1*Q2)/R^2
well, plug in your numbers!
and, of course, opposite charges attract.
i got -375,000,000
is it correct?
To compute the electrical force between Q1 and Q2, we can use the formula:
F = k * (Q1 * Q2) / R^2
Where:
k = 9x10^9 N*m^2/C^2 (Coulomb's constant)
Q1 = 3 microcoulombs (3x10^-6 C)
Q2 = -2 microcoulombs (-2x10^-6 C)
R = 12 cm (converted to meters: 12/100 = 0.12 m)
Now, let's substitute the given values into the formula:
F = (9x10^9 N*m^2/C^2) * ((3x10^-6 C) * (-2x10^-6 C)) / (0.12 m)^2
F = 3.0 N
Since the electrical force (F) calculated above is positive, the charges Q1 and Q2 repel each other.
To compute the electrical force between the charges Q1 and Q2 and determine if it is attractive or repulsive, we will use the given formula:
F = k * (Q1 * Q2) / R^2
where:
F = electrical force between the charges
k = Coulomb's constant = 9 x 10^9 N*m^2/C^2
Q1 and Q2 = charges (in microcoulombs)
R = distance between the charges (in meters)
Given: Q1 = 3 microcoulombs, Q2 = -2 microcoulombs, R = 12 cm = 0.12 meters
Plugging in the values in the formula:
F = (9 x 10^9 N*m^2/C^2) * (3 x 10^-6 C) * (-2 x 10^-6 C) / (0.12 m)^2
Now, let's calculate step by step:
1. Multiply the charges Q1 and Q2: (3 x 10^-6) * (-2 x 10^-6) = -6 x 10^-12 C^2
2. Square the distance R: (0.12 m)^2 = 0.0144 m^2
Now substitute the values back into the formula:
F = (9 x 10^9 N*m^2/C^2) * (-6 x 10^-12 C^2) / (0.0144 m^2)
Simplifying the calculation:
F = - 3 x 10^-4 N
Therefore, the electrical force between the charges is -3 x 10^-4 N. Since the force is negative, it is considered attractive.