Use a graphing calculator to solve the equation -3 cos t = 1 in the interval from 0 ≤ θ ≤ 2π Round to the nearest hundredth.
so i put it in a graphing calculator online and now i understand what i am supposed to write or do can someone please help me?
-3 cos t = 1
first make sure your setting is in radians, look for a DRG key, press it
until you see RAD in your display.
simplify the equation to
cos t = -1/3
forget about the minus in -1/3 for the moment.
enter:
2ndF
cos
(1÷3)
=
to get 1.230959...
That would be you angle in "standard position", that is, the
corresponding angle if we had been in quadrant I
but since the cosine is negative we must be in quads II or III
so t = π - 1.230959.. = appr 1.9106
or
t = π + 1.230959.. = appr 4.3726
check my answer by plugging it in the original equation
Hint: it works
i don't know where those displays is on the graphic calculator online but thank you for explaining it to me and giving me the answers.
You don't really need a fancy graphic calculator like the TI-84, any cheap
scientific calculator has this stuff. I am using a 25 year old SHARP. I also have
one bought at a Dollar Store for $2.99, does the same thing.
Sure! To solve the equation -3 cos(t) = 1 in the interval 0 ≤ θ ≤ 2π using a graphing calculator, follow these steps:
1. Enter the equation into the graphing calculator. You can use the key for "cos" (cosine) and the minus sign.
The equation should be: -3*cos(t) = 1.
2. Set the calculator to radian mode. This ensures that the calculator interprets the angles correctly in radians.
3. Set the graphing window to show the interval 0 ≤ θ ≤ 2π. This will display the solution within the desired range.
4. Find the intersection point(s) between the graph of the equation -3*cos(t) and the line y = 1 on the calculator's graph screen.
5. Read the x-coordinate(s) of the intersection point(s). These are the solutions to the equation.
6. Round the solution(s) to the nearest hundredth if required.
That's it! By following these steps, you can use a graphing calculator to find the solutions to the given equation within the specified interval.