physics

a bullet of mass 10.0g sprites a wall with a velocity of 500m/s ,determine the work done by the wall on the bullet which penetrate 0.10m .

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  1. V^2 = Vo^2 + 2a*d = 0.
    500^2 + 2a*0.1 = 0,
    a = -1,25*10^6 m/s^2.

    F = M*a = 1*10^-2 * 1.25*10^6 = -1.25*10^4 = -12,500 N.
    Work = F*d = 12,500 * 0.1 = -1250 Joules.

    Note: The negative sign means that the force opposes the bullet motion.

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    posted by Henry2,

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