Physics

A 2kg block rests at the edge of a platform that is 10m above ground level.The block launched horizontally from the edge of the platform with an initial speed of 3m/s. Air resistance is negligible.what is the time taken for the block to reach the ground?

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1. time to fall: t=sqrt(2h/g)
solve that for time.

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2. vertical free fall equation ... h = -1/2 g t^2 + Vo t + Ho

0 = -1/2 * 9.8 * t^2 + 0 + 10 = -4.9 t^2 + 10

the horizontal motion has no effect on the flight time

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3. 0.5g*t^2 = 10.
4.9t^2 = 10,
t = 1.43 s.

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4. what??????????????????????????????????

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