# Calculus

Find derivative: (write answer as single fraction)

y=ln((4x-1)/x^3)

So far I have:
y'=(4/(4x-1))-3/x
How do I write as single fraction

let u= (4x-1) v= x^-3

dy/dx= d y/d(uv) * d(uv)/dx

dy/duv= 1/uv

d(uv)/dx= udv/dx + v du/dx

put it together.

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