Which equation shows a correct factored form of the quadratic equation 3x+28=x2?
0=(x−4)(x+7)
0=(x+4)(x+7)
0=(x+4)(x−7)
0=(x−4)(x−7)
What are your choices?
Okay, great. And where are you getting stuck on this problem?
at x=2
x = 2 is nowhere in your equation.
on the the other side of the equal sighn
That's not x=2. It's x squared.
3x+28 = x^2
now rearrange things into the standard form:
x^2-3x-28 = 0
Now is when you factor it.
Which two factors of 28 differ by 3?