The kinetic energy of a bullet fired from a gun is 40joules,if the mass of the bullet in 0.1kg calculate the initial speed of the bullet.
I don't know the answer to it.
KE = 1/2 mv^2
so, plug in your numbers and find v
80
The work is good
To calculate the initial speed of the bullet, we can use the formula for kinetic energy:
Kinetic Energy (KE) = (1/2) * mass * velocity^2
Given that the kinetic energy of the bullet is 40 joules and the mass of the bullet is 0.1 kg, we can rearrange the formula to solve for velocity:
KE = (1/2) * mass * velocity^2
Rearranging the formula, we have:
velocity^2 = (2 * KE) / mass
Substituting the given values, we get:
velocity^2 = (2 * 40 joules) / 0.1 kg
Simplifying the equation, we have:
velocity^2 = 800 joules / 0.1 kg
velocity^2 = 8000 m^2/s^2
To find the velocity, we take the square root of both sides:
velocity = √(8000 m^2/s^2)
velocity ≈ 89.44 m/s
Therefore, the initial speed of the bullet is approximately 89.44 m/s.