In an examination conducted for 60 candidates,the number of candidate who passed in Maths is 15 more than those who passed science and 7 failed both subject 12 candidates passed both subject
1.Draw a Venn diagram to illustrate this information
2.How many candidates passed Maths
3.How many candidates passed Science
4.Exactly one of the two subjects
Please the solution for question above:
Let s=Science
(s+15)=Mathematics
U=60
Passed both subj=12
Failed in both sub=7
Now sum all together and equate to the U
(s+12+(15+s)+7=60
Therefore,s=13//.
Qns2,
Passed Math =(15+13)=28//
Qns3,
Passed Science=13
Qns4,
Passed one subject=(s-12,i.e 13-12=1//)+ (15+s-12,i.e 28-12=14//),therefore,one subject=(1+14=15)//
in an examination conducted for 60 candidates,the number who passed in mathematics are 15 more than those who passed in science and 7 failed in both subject. 12 candidates passed in both subject
Please I don't get you!!
I assume you can draw the Venn diagram. If not google is your friend.
If s passed science, then s+15 passed math. So,
s + (s+15) - 12 = 60-7
now you can answer questions 2,3
For #4, 60-7 passed something; 12 passed both, so 60-7-12 passed one or the other, but not both.
Please take your time to explain
The Venn diagram
I need the Venn diagram for my homework
I do not understand
I don’t understand so pls explain it step by step
i dont understand
I want the Venn diagram for this question
U=60
M=X+15
S=X
(M n S)=12
(M n S)'=7
maths=(X+15)-12+X-12+12+7=60
=(X+3+X+7=60
=2X+10=60
=2X=60-10
=2X=50
2X/2=50/2
=X=25
Mathematics=X+15
=25+15
=40
Therefore,maths is 40
Science=X
=25
Therefore, science is 25
Exactly one of the subject=(40-12)+(25-12)
=28+13
=41
Therefore,41students passed in at least one subject