A spring 30cm long is stretched to 35cm by a load of 5 0.0005 what will be its length when stretched by the same force assuming that the elastic limit is not exided
To find the length of the spring when stretched by the same force, we can use Hooke's Law, which states that the force exerted on a spring is directly proportional to the extension of the spring.
Hooke's Law can be expressed as:
F = k * x
where F is the force applied to the spring, k is the spring constant, and x is the extension of the spring.
In this case, we know that the initial length of the spring (L0) is 30 cm, the extension (x0) is 35 cm - 30 cm = 5 cm, and the force (F0) applied is 0.0005.
Now, we can calculate the spring constant (k) by rearranging Hooke's Law equation:
k = F0 / x0
Substituting the known values:
k = 0.0005 / 5 = 0.0001 N/cm
Now, we can use Hooke's Law to find the length of the spring when stretched by the same force (L):
F = k * x
L = L0 + x
Rearranging the equation, we get:
x = L - L0
Substituting in the values:
x = L - 30
And solving for L, we have:
L = x + 30
Now, we can plug in the values to find L when F = F0:
L = x + 30
L = 5 + 30
L = 35 cm
Therefore, the length of the spring when stretched by the same force will be 35 cm.