How many moles of sulfur dioxide are produced when 72.0 grams of water is produced by the process:
2H2S + 3O2 ---> 2H2O +2SO2
72.0g of H2O is roughly 4 moles of H2O. So, 4 moles of SO2 are produced, according to the balanced reaction.
To find the number of moles of sulfur dioxide produced, we need to use the given mass of water produced.
1. Start by calculating the molar mass of water (H2O).
The molar mass of hydrogen (H) is 1.008 g/mol, and the molar mass of oxygen (O) is 16.00 g/mol. Since water has two hydrogen atoms and one oxygen atom, the molar mass of water is:
(2 * 1.008 g/mol) + (1 * 16.00 g/mol) = 18.02 g/mol
2. Next, use the molar ratio from the balanced equation.
Based on the balanced equation:
2H2S + 3O2 ---> 2H2O + 2SO2
The molar ratio between water (H2O) and sulfur dioxide (SO2) is 2:2 or 1:1.
3. Convert the given mass of water produced to moles.
Given: Mass of water = 72.0 g
To convert grams to moles, divide the mass by the molar mass:
72.0 g / 18.02 g/mol ≈ 3.998 mol (rounded to four decimal places)
Therefore, 72.0 grams of water is approximately equal to 3.998 moles of water.
4. Finally, since the molar ratio between water and sulfur dioxide is 1:1, the number of moles of sulfur dioxide produced is also 3.998 moles.
Therefore, when 72.0 grams of water is produced, approximately 3.998 moles of sulfur dioxide is also produced.
To find out how many moles of sulfur dioxide (SO2) are produced when 72.0 grams of water (H2O) is produced, we need to use the given balanced equation and the molar masses of the substances involved.
First, let's start by calculating the number of moles of water produced using its molar mass. The molar mass of water (H2O) is:
H: 1.01 g/mol x 2 = 2.02 g/mol
O: 16.00 g/mol
Adding these values gives us a molar mass of water (H2O) of:
2.02 g/mol + 16.00 g/mol = 18.02 g/mol
Now, we can use the molar mass and the given mass of water (72.0 grams) to calculate the number of moles of water produced:
Number of moles = Mass / Molar mass = 72.0 g / 18.02 g/mol = 3.9956 mol
From the balanced equation, we can see that for every 2 moles of water produced, 2 moles of sulfur dioxide (SO2) are also produced. Therefore, we can conclude that:
3.9956 mol of water produces 3.9956 mol of sulfur dioxide.
So, 3.9956 moles of sulfur dioxide are produced when 72.0 grams of water is produced.