solve the system using elimination 4x-7y=3
x-7y=15
the answer is (6,3)
(6,3)
Why did the mathematician want to use elimination to solve the system of equations? Because they couldn't catch the bus! Alright, let's get to it.
To solve this system using elimination, we'll eliminate the variable "x".
First, let's multiply the second equation by 4 to make the coefficients of "x" in both equations the same.
4(x-7y) = 4(15)
Simplifying, we get:
4x - 28y = 60
Now, let's subtract the first equation from this new equation:
(4x - 28y) - (4x - 7y) = 60 - 3
Simplifying, we have:
-21y = 57
Dividing both sides by -21, we get:
y = -57/21
Simplifying further, we have:
y = -19/7
Now that we have the value of y, let's substitute it back into one of the original equations to find the value of x.
Using the first equation, we have:
4x - 7(-19/7) = 3
Simplifying, we get:
4x + 19 = 3
Subtracting 19 from both sides, we have:
4x = 3 - 19
4x = -16
Dividing both sides by 4, we find:
x = -16/4
Simplifying, we have:
x = -4
Therefore, the solution to the system of equations is: x = -4 and y = -19/7.
To solve the system of equations using elimination, we need to eliminate one variable by adding or subtracting the two equations. In this case, since both equations have a coefficient of -7y, we can subtract the second equation from the first equation to eliminate the variable y.
Let's start by setting up the equations:
Equation 1: 4x - 7y = 3
Equation 2: x - 7y = 15
Now, we can subtract Equation 2 from Equation 1:
(4x - 7y) - (x - 7y) = 3 - 15
Simplifying, we eliminate the y variable:
4x - 7y - x + 7y = -12
Combine like terms:
3x = -12
Divide both sides of the equation by 3:
x = -12 / 3
x = -4
Now that we have the value of x, we can substitute it back into one of the original equations to find the value of y. Let's use Equation 2:
x - 7y = 15
-4 - 7y = 15
Add 4 to both sides:
-7y = 19
Divide both sides by -7:
y = 19 / -7
y = -19/7
So, the solution to the system of equations is x = -4 and y = -19/7.
a{12/-5},{10/7}
b(-1,2)
c(6,3)
d[1,1/7]
4 x - 7 y = 3
-
x - 7 y = 15
___________
4 x - x - 7 y - ( - 7 y ) = 3 - 15
3 x = - 12
Divide both sides by 3
x = - 12 / 3
x = - 4
Replace x = - 4 in equation x-7y=15
- 4 - 7 y = 15
Add 4 to both sides
- 4 - 7 y + 4 = 15 + 4
- 7 y = 19
Divide both sides by - 7
y = 19 / - 7
y = - 19 / 7
Eq1: 4x - 7y = 3.
Eq2: x - 7y = 15.
subtract Eq2 from Eq1 to find X:
Diff.: 3x + 0 = -12,
X = -4.
In Eq2, replace X with -4 and solve for Y:
-4 - 7y = 15,