A car mass 800kg starts from rest and accelerates at 1.2m/s^2 .determine the final velocity attained by the car
that depends on how long it accelerates. Just note that
v = at
To determine the final velocity attained by the car, we can use the equation of motion:
v = u + at
where:
v = final velocity,
u = initial velocity (which is 0, as the car starts from rest),
a = acceleration,
t = time.
Given:
u = 0 m/s (initial velocity),
a = 1.2 m/s^2 (acceleration).
Since the car starts from rest, the initial velocity u is 0.
Now, to find the time it takes for the car to attain its final velocity, we can use another equation of motion:
v^2 = u^2 + 2as
where:
v = final velocity,
u = initial velocity,
a = acceleration,
s = displacement.
Since the car starts from rest, the initial velocity u is 0. The displacement s is not provided, but since we are only interested in the final velocity, we can assume that the car has traveled a sufficient distance to attain its final velocity.
Therefore, we can rewrite the equation as:
v^2 = 2as
Now, let's rearrange the equation to solve for v:
v^2 = 2as
v = √(2as)
Substituting the given values:
v = √(2 * 1.2 * s)
Since we don't have the displacement value, we can't calculate the final velocity using this approach. Please provide the displacement traveled by the car, and we will be able to calculate the final velocity using the equation v = √(2as).