If U={natural numbers less than 20} and N={factors of 18}, what is N’?
What am I supposed to do?
I know the factors of 18 are 1, 2,3,6, 9, & 18.
I know the natural numbers less than 20 are 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20. So what am I supposed to be looking for?
Thank you!
natural number that are less than 18
N' is the notation for "N compliment"
or "not N"
so in your list for U, which numbers are NOT factors of 18 ?
Thanks
Ah, I see you're puzzled about finding N' (pronounced "N prime"). Don't worry, I'm here to help!
In this case, N' refers to the complement of the set N within the set U. In other words, it consists of all the elements in U that are not in N.
Since U contains all the natural numbers less than 20, and N contains the factors of 18, we just need to figure out which elements from U are not in N.
Well, in N, we have 1, 2, 3, 6, 9, and 18. So, the elements of U that are not in N are 4, 5, 7, 8, 10, 11, 12, 13, 14, 15, 16, 17, and 19.
Therefore, N' (pronounced "N prime") is the set {4, 5, 7, 8, 10, 11, 12, 13, 14, 15, 16, 17, 19}.
Hope that clarifies things for you in a humorous way! If you have any more questions, feel free to ask.
To find the set N', you need to subtract the elements of set N from the universal set U. In this case, U represents the natural numbers less than 20, and N represents the factors of 18.
First, let's list the elements of set N, the factors of 18: {1, 2, 3, 6, 9, 18}.
Next, let's list the elements of set U, the natural numbers less than 20: {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19}.
Now, to find the set N', we need to subtract the elements of set N from set U.
To do this, you can mentally or physically cross out the elements of set N from set U. The remaining elements will form set N'.
In this case, when you cross out the factors of 18 from the natural numbers less than 20, you are left with the set N', which is {4, 5, 7, 8, 10, 11, 12, 13, 14, 15, 16, 17, 19}.
So, N' is equal to {4, 5, 7, 8, 10, 11, 12, 13, 14, 15, 16, 17, 19}.