Calculus

Rolle's theorem cannot be applied t the function f(x)= ln(x+2) on the interval [-1,2] because

a) f is not differentiable on the interval [-1,2]
b) f(-1)≠ f(2)
c) All of these
d) Rolle's theorem can be applied to f(x)= ln(x+2) on the interval [-1,2]

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  1. ln(x+2) is defined and differentiable on (-2,∞) so (a) is out
    Rolle's Theorem is a special case of the Mean Value Theorem, where f(a) = f(b)
    Clearly, that is not the case here...

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