I've been struggling with algebra since I started and don't understand hardly any of it and I have this problem 9xy (2/3x)^3=( a0/ ' ^a0/)x^4y
I really need help I have several problems like this and don't know what to do someone please explain how I solve this

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  1. what does ( a0/ ' ^a0/) mean ?
    however, to get you started,

    9xy (2/3 x)^3 = 9xy * (2/3)^3 * x^3
    = 9xy * 8/27 * x^3
    = 8/3 x^4 y

    Maybe you can sort out the other side, and then solve for something or other.

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