A worker pushes a crate horizontally across a warehouse floor with a force of 245 N at an angle of 55 degrees below the horizontal. How much of the worker’s force is not used to move the crate?
200.69 n
419.95 n(my choice/guess)
357.71 n
191.32 n
You stand in top a building 44 m talk with a water ballon. You drop the water ballon from rest. How fast is the balloon moving when it is halfway down the building?
20.78 m/s
39.81 m/s(my choice/guess)
19.68 m/s
26.92 m/s
He only pushed with 245 !!, no way bigger component
245 - 245 cos 55 = 245 (1 - cos 55)
falls 22 m from stop at 9.81 m/s^2
22 = (1/2)(9.81) t^2
so
t^2 = 4.48
t = 2.12 seconds
v = 9.81 t = 20.78 m/s
or for first one, what is force down (not used)
245 * sin 55 = 200.69
2. V^2 = Vo^2 + 2g*d = 0 + 19.6*22 = 431.2.
V = 20.8 m/s.
To find out how much of the worker's force is not used to move the crate, we can break down the force into its horizontal and vertical components.
The horizontal component of the force can be found by multiplying the total force by the cosine of the angle: horizontal component = 245 N * cos(55°) ≈ 138.32 N.
The vertical component of the force can be found by multiplying the total force by the sine of the angle: vertical component = 245 N * sin(55°) ≈ 200.69 N.
Since the worker is pushing the crate horizontally, the vertical component of the force is not used to move the crate. Therefore, the answer to the first question is 200.69 N.
To find out how fast the water balloon is moving when it is halfway down the building, we can use the equation for the final velocity of an object in free fall:
vf^2 = vi^2 + 2gh
Where vf is the final velocity, vi is the initial velocity (which is 0 since the balloon is dropped from rest), g is the acceleration due to gravity (approximately 9.8 m/s^2), and h is the distance the balloon has fallen (which is halfway down the building, so 44 m / 2 = 22 m).
Simplifying the equation, we get:
vf^2 = 0 + 2 * 9.8 m/s^2 * 22 m
vf^2 = 2 * 9.8 m/s^2 * 22 m
vf^2 = 431.2 m^2/s^2
Taking the square root of both sides, we find:
vf ≈ √431.2 m^2/s^2 ≈ 20.78 m/s
Therefore, the answer to the second question is 20.78 m/s.