I have the following question on a warm-up :
What is the equation of the line that passes through the point {-2, 2} and has a slope of 5?
Can someone help me to figure out the answer.
review the point-slope form. You will easily see that the equation is
y-2 = 5(x+2)
wouldn't it be y + 2 = 5(x+2) ?
nvm, I understand now
THANKS FOR THE HELP :)
(-2, 2), (x, y)
m = (y-2)/(x+2) = 5,
y-2 = 5x + 10,
Y = 5x + 12.
Or:
Y = mx + b.
2 = 5*(-2) + b.
b = 12.
Y = 5x + 12.
Of course! I can help you with that.
To find the equation of a line given a point and a slope, you can use the point-slope form of the equation of a line, which is:
y - y1 = m(x - x1)
Where (x1, y1) is a point on the line, and m is the slope of the line.
In this case, you have the point (-2, 2) and a slope of 5.
Now, let's substitute the values into the equation:
y - 2 = 5(x - (-2))
Simplifying the equation, we get:
y - 2 = 5(x + 2)
Expanding the equation further:
y - 2 = 5x + 10
Finally, let's isolate y by adding 2 to both sides:
y = 5x + 12
So, the equation of the line that passes through the point (-2, 2) and has a slope of 5 is y = 5x + 12.