-4x + 2y =2
y= -6x + 1
Ideally set up for substitution.
sub the 2nd into the 1st:
-4x + 2y =2
-4x + 2(-6x + 1) = 2
now you have only x's, expand and solve for x, then
sub that into the original 2nd equation.
let me know what you get.
x=0 & y=1
To find the solution to the system of equations:
-4x + 2y = 2 ...(1)
y = -6x + 1 ...(2)
We can use the method of substitution.
1. Start by solving equation (2) for one variable, preferably for y since it is isolated:
y = -6x + 1
2. Now substitute this expression for y in equation (1):
-4x + 2(-6x + 1) = 2
3. Simplify the equation by distributing the 2:
-4x - 12x + 2 = 2
4. Combine like terms:
-16x + 2 = 2
5. Move the constants to the other side:
-16x = 2 - 2
-16x = 0
6. Divide both sides by -16:
x = 0 / -16
x = 0
7. Substitute the value of x back into equation (2) to solve for y:
y = -6(0) + 1
y = 1
Therefore, the solution to the system of equations is x = 0 and y = 1.