# Physics

A plane flying at 75 m/s, was diving at an angle of 40 degrees below the horizontal when one of it's wheels fall off. The wheel hits the ground 8.5 s after it fell off the plane. I know the x and y components of the wheel as 57.5 and 48.2 m/s, respectively. But I don't know how to solve the other problems:
1. At what height did the wheel fall off the plane?
2. What horizontal distance did the wheel travel?
3. What was the wheel's velocity when it hit the ground?

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1. the wheel had an initial vertical velocity, and was then accelerated by gravity for 8.5 s

final vel y = init vel y + (8.5 s * g)

ave vel y = (final y + init y) / 2

ave vel y * 8.5s = height

horiz dist = x vel * 8.5 s

init K.E. + (m g h) = fin K.E.

(init vel)^2 + (2 g h) = (fin vel)^2

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2. 1. h = Vo*t + 0.5g*t^2 = 48.2 + 4.9*8.5^2 =

2. Xo * t = 57.5 * 8.5 =

3. V = Vo + g*t = 48.2 + 9.8*8.5 =

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