What is the prime factorization of 540?
I am clueless
start with 2 and work your way up
540 / 2 = 270
270 / 2 = 135
135 / 3 = 45
45 / 3 = 15
15 / 3 = 5
2^2 * 3^3 * 5
So, the prime factorization of 540 can be written as 22 × 33 × 51 where 2, 3, 5 are prime.
Thank you.... and I am sorry I didn't mean to
To find the prime factorization of 540, we need to determine which prime numbers can divide evenly into 540. Here's a step-by-step explanation of how to find the prime factorization:
1. Begin by dividing the number by the smallest prime number, which is 2. Is 540 divisible by 2? Yes, since it's an even number. Divide 540 by 2, and you get 270.
2. Now, we repeat the same process with the quotient 270. Divide it by 2 again, and you get 135.
3. Continue dividing by 2 until the quotient is no longer divisible by 2. In this case, we divide 135 by 2 and get 67.5. Since 67.5 is not a whole number, we know that 135 is no longer divisible by 2.
4. Move on to the next prime number, which is 3. Divide the current quotient, 135, by 3. The result is 45.
5. Again, repeat the process. Divide 45 by 3 to get 15.
6. Continue dividing by 3 until the quotient is no longer divisible by 3. In this case, we divide 15 by 3 again to get 5. Since 5 is a prime number, we can stop here because further division is not possible.
7. Therefore, the prime factorization of 540 is 2 x 2 x 3 x 3 x 3 x 5 or expressed with exponents: 2^2 x 3^3 x 5.
So, the prime factorization of 540 is 2^2 x 3^3 x 5.
Please don't post the same question again after you've already gotten two good answers.
https://www.jiskha.com/questions/1780693/What-is-the-prime-factorization-of-540-Can-you-help-me