A bicycle accelerates from 0.0 m/s to 42 m/s in 5.9 s. What distance does it travel?
____ m
distance = average velocity * time
d = [(0.0 m/s + 42 m/s) / 2] * 5.9 s
Thank you!
To find the distance the bicycle travels, we can use the formula for distance traveled during uniform acceleration:
distance = (initial velocity * time) + (1/2 * acceleration * time^2)
We are given the initial velocity (0.0 m/s), the final velocity (42 m/s), and the time (5.9 s). However, we are not given the acceleration directly. We can find the acceleration using the following equation:
acceleration = (final velocity - initial velocity) / time
Plugging in the given values, we can calculate the acceleration:
acceleration = (42 m/s - 0.0 m/s) / 5.9 s
acceleration = 42 m/s / 5.9 s
acceleration = 7.118 m/s^2 (rounded to three decimal places)
Now that we have the acceleration, we can plug it back into the original formula to find the distance:
distance = (0.0 m/s * 5.9 s) + (1/2 * 7.118 m/s^2 * (5.9 s)^2)
distance = 0 + (1/2 * 7.118 m/s^2 * 34.81 s^2)
distance = (1/2 * 7.118 m/s^2 * 34.81 s^2)
distance = 120.489 m (rounded to three decimal places)
Therefore, the bicycle travels approximately 120.489 meters.