An object is thrown directly downwards from a height of 60m with an initial velocity of 11m/s. What will be its velocity on impact with the ground?

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  1. You would be solving:

    -4.9t^2 - 11t + 60 = 0

    sub into .....
    velocity = -9.8t - 11

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  2. V^2 = Vo^2 + 2g*h = 11^2 + 19.6*60 = 1297.
    V = 36.0 m/s.

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