Math

Find F(x) such that F'(x) = sec^4 (x) and F(pi/4) = 0

F'(x) = sec^4
F(x) = (1/3)tan^3 (x) + tan(x) + C

Now I don't understand the last part of the question?
Just replace x by pi/4?

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  1. your integral is correct.
    so replace x with π/4
    F(x) = (1/3)tan^3 (x) + tan(x) + C
    F(π/4) = (1/3)tan^3 (π/4) + tan(π/4) + C

    What part of this don't you understand?
    You should of course
    know that tan(π/4) = 1 , (tan45° = 1)

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