A child traveling 2 m/s on a sled passes her younger brother. If her average acceleration on the sledding hill is 2 m/s2, how fast is she traveling when she passes her older brother 6 s later?
2 m/s + (6 s * 2 m/s^2)
To find the child's final speed when she passes her older brother, we need to use the formula for constant acceleration:
v = u + at
Where:
v = final velocity
u = initial velocity
a = acceleration
t = time
Given:
Initial velocity, u = 2 m/s
Acceleration, a = 2 m/s²
Time, t = 6 s
Now let's substitute the given values into the formula:
v = 2 m/s + (2 m/s² × 6 s)
First, let's calculate the multiplication:
v = 2 m/s + (12 m/s)
Now, let's add the velocities together:
v = 14 m/s
Therefore, when the child passes her older brother 6 seconds later, she is traveling at a speed of 14 m/s.