Find the image of S(–1, –3) after a reflection across the line y = –2.
To find the image of a point after a reflection across a line, we can follow these steps:
1. Draw the line of reflection. In this case, the line of reflection is y = -2.
2. Determine the distance from the point to the line of reflection. We can find this by calculating the vertical distance or the difference in the y-coordinates between the point and the line.
The distance from the point S(-1, -3) to the line y = -2 is:
|-3 - (-2)| = |-3 + 2| = 1
3. Move the point twice the distance from the line of reflection, perpendicular to the line, in the opposite direction.
Since the distance from the line of reflection is 1, we move the point twice that distance, which is 2 units. Since the point is below the line of reflection, we move it upward.
4. Locate the new point. Start from the point S(-1, -3) and move it 2 units vertically above the line y = -2.
The new point is S'(-1, 0).
Therefore, after a reflection across the line y = -2, the image of S(-1, -3) is S'(-1, 0).
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I think you can get it if you try hard enough
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I am sure you will get it once you plot and graph it.
y= -2 is a horizontal line 2 units below the x-axis.
Let me know what you get.